!set titb=nextstep
!set keyw=
!set datm=20070412
!set prev=
!set next=
!set upbl=main
!set dat1=19000101
!set dat2=24000101

!if $wims_read_parm!=$empty
 !goto $wims_read_parm
!endif

!exit

:content

!read primitives.phtml 1, embed, definition, &nbsp; 
<pre class="fichier">
<div class="variable">
$m_title$m_lbrac sommation 4 $m_rbrac 
$m_computeanswer$m_lbrac no $m_rbrac
$m_language$m_lbrac fr $m_rbrac
$m_author$m_lbrac Sophie Lemaire $m_rbrac 
$m_email$m_lbrac Sophie.Lemaire@math.u-psud.fr $m_rbrac 
$m_format</tt>$m_lbrac html $m_rbrac 
$m_integer</tt>$m_lbrac n=$m_randint(20<tt class="w">..</tt>40)*10 $m_rbrac 
$m_text</tt>$m_lbrac liste=somme simple sur l'indice \(i), somme simple sur l'indice \(j) $m_rbrac <tt class=comm>
$m_text</tt>$m_lbrac c=$m_item(1,\liste) $m_rbrac <tt class=comm>
$m_text</tt>$m_lbrac d=$m_item(2,\liste) $m_rbrac <tt class=comm>
$m_text</tt>$m_lbrac nb=1,2 $m_rbrac <tt class=comm>
$m_text</tt>$m_lbrac nstep=<tt class=reply>reply1</tt> $m_rbrac <tt class=comm>
$m_nextstep</tt>$m_lbrac \nstep $m_rbrac </div>
<div class="statement">
$m_statement$m_lbrac Soit &#92;(E = \$m_lbrac (i,j)\in \NN^2, i + j = \n\ $m_rbrac \) et   
&#92;(\$m_lbrac f(i,j), (i,j) \in \ZZ^2\ $m_rbrac \) 
une famille de réels positifs. &lt;p>
  <tt class=comm>\if</tt>$m_lbrac \step = 1 $m_rbrac$m_lbrac  1 - Pour exprimer la somme &#92;(\sum_$m_lbrac (i,j)\in E $m_rbrac f(i,j)) vous voulez &#58; 
 &lt;ul> 
  &lt;li><tt class=comm>\embed</tt>$m_lbrac <tt class=reply>reply1</tt>, 1 $m_rbrac &lt;/li>
  &lt;li><tt class=comm>\embed</tt>$m_lbrac <tt class=reply>reply1</tt>, 2 $m_rbrac &lt;/li>
 &lt;/ul> 
<tt class="comm">\exit</tt>$m_lbrac $m_rbrac  $m_rbrac <tt class=comm>
\if</tt>$m_lbrac \step >= 2 $m_rbrac$m_lbrac  
  Complétez la formule ci-dessous &#58;
     <tt class=comm>\if</tt>$m_lbrac \test1 <tt class="op">issametext</tt> \c $m_rbrac$m_lbrac  
       &lt;table align="center">
       &lt;tr> &lt;td>&lt;/td>&lt;td><tt class=comm>\embed</tt>$m_lbrac <tt class=reply>reply2</tt>, 5 $m_rbrac &lt;/td>&lt;td> &lt;/td>&lt;/tr>
       &lt;tr>&lt;td>&#92;(\sum_$m_lbrac (i,j)\in E $m_rbrac f(i,j))  = &lt;/td>
           &lt;td>&#92;(\sum)&lt;/td>
           &lt;td>&#92;(f)(\(i),<tt class=comm>\embed</tt>$m_lbrac <tt class=reply>reply4</tt>, 5 $m_rbrac )&lt;/td>
       &lt;/tr>
       &lt;tr>&lt;td> &lt;/td>&lt;td>&#92;(i) = <tt class=comm>\embed</tt>$m_lbrac <tt class=reply>reply3</tt>, 5 $m_rbrac &lt;/td> &lt;td>&lt;/td>&lt;/tr>
&lt;/table> $m_rbrac$m_lbrac  
   &lt;table align="center">
     &lt;tr>&lt;td>&lt;/td>&lt;td><tt class=comm>\embed</tt>$m_lbrac <tt class=reply><tt class=reply>reply2</tt></tt>, 5 $m_rbrac &lt;/td>&lt;td> &lt;/td>&lt;/tr>
     &lt;tr>&lt;td>&#92;(\sum_$m_lbrac (i,j)\in E $m_rbrac f(i,j))  = &lt;/td>
         &lt;td>&#92;(\sum)&lt;/td>
         &lt;td>\(f)(<tt class=comm>\embed</tt>$m_lbrac <tt class=reply><tt class=reply>reply5</tt></tt>, 5 $m_rbrac ,\(j))&lt;/td>
    &lt;/tr>
    &lt;tr>&lt;td> &lt;/td>&lt;td>&#92;(j ) = 
          <tt class=comm>\embed</tt>$m_lbrac <tt class=reply>reply3</tt>, 5 $m_rbrac &lt;/td>&lt;td>&lt;/td>&lt;/tr>
   &lt;/table> $m_rbrac  $m_rbrac  $m_rbrac </div>
<div class="variable">
$m_answer$m_lbrac $m_rbrac $m_lbrac \test1;\liste $m_rbrac$m_lbrac  <tt class="type">type=radio</tt> $m_rbrac$m_lbrac  <tt class="type">weight=0</tt> $m_rbrac <tt class=comm>
\answer</tt>$m_lbrac $m_rbrac$m_lbrac  \n $m_rbrac$m_lbrac  <tt class="type">type=numeric</tt> $m_rbrac 
$m_answer$m_lbrac $m_rbrac$m_lbrac  0 $m_rbrac$m_lbrac  <tt class="type">type=numeric</tt> $m_rbrac 
$m_answer$m_lbrac $m_rbrac$m_lbrac  \n-i,i,j $m_rbrac$m_lbrac  <tt class="type">type=function</tt> $m_rbrac 
$m_answer$m_lbrac $m_rbrac$m_lbrac  \n-j,i,j $m_rbrac$m_lbrac  <tt class="type">type=function</tt> $m_rbrac <tt class=comm>
$m_text</tt>$m_lbrac nstep = (\step = 2) <tt class="op">and</tt> (\test1 <tt class="op">issametext</tt> \c) ? <tt class=reply>reply2</tt>, <tt class=reply>reply3</tt>, <tt class=reply>reply4</tt> $m_rbrac <tt class=comm>
\text</tt>$m_lbrac nstep = (\step = 2) <tt class="op">and</tt> (\test1 <tt class="op">issametext</tt> \d) ? <tt class=reply>reply2</tt>, <tt class=reply>reply3</tt>, <tt class=reply>reply5</tt> $m_rbrac <tt class=comm>
\feedback</tt>$m_lbrac (\step >= 2) <tt class="op">and</tt> (\test1 <tt class="op">issametext</tt> \c) $m_rbrac$m_lbrac  
    &lt;i>NB &#58; On peut aussi exprimer &#92;(\sum_$m_lbrac (i,j)\in E $m_rbrac f(i,j)\) à l'aide d'\d&lt;/i> $m_rbrac <tt class=comm>
\feedback</tt>$m_lbrac (\step >= 2) <tt class="op">and</tt> (\test1 <tt class="op">issametext</tt> \d) $m_rbrac$m_lbrac  
    &lt;i>NB &#58; On peut aussi exprimer &#92;(\sum_$m_lbrac (i,j)\in E $m_rbrac f(i,j)\) à l'aide d'\c&lt;/i> $m_rbrac <tt class=comm>
\feedback</tt>$m_lbrac  (\step >= 2) <tt class="op">and</tt> (\test1 <tt class="op">issametext</tt> \c) <tt class="op">and</tt> j <tt class="op">isin</tt> \reply4 $m_rbrac$m_lbrac  
Si vous décidez d'exprimer cette somme double comme une somme simple en 
\(i), pourquoi mettez-vous un \(j) dans votre réponse ? $m_rbrac </div>
</pre>
