\title{Powers}
\language{en}
\range{-0.9..0.9}
\author{Gang XIAO}
\email{xiao@unice.fr}
\computeanswer{yes}
\format{html}
\precision{10000}

\integer{power=random(2..19)}
\integer{r1=random(1,1,1,2)}
\integer{p=\power%2}
\text{ff=random(f(x^{\power}), f(x)^{\power})}
\text{f=the function \(x\rightarrow \ff)}
\text{F1=item(\r1,\f,\( f))}
\text{F2=item(\r1,\(f), \f)}
\text{bad=Yes,No}
\text{good=\p=0 and \r1=1?No:Yes}

\statement{Let \(f: \RR\rightarrow\RR) be a real function. Is the following
statement true?

<center>
 If \F1 is continuous, then \F2 is continuous.
 </center>
}

\choice{}{\good}{\bad}

\hint{The function \(x\rightarrow x^n) is bijective if n&gt;0 is odd,
but it is not bijective if n is even.
}

